You will want to use a SPDT momentary contact (On)-Off-(On) switch.
Can be used for both the DZ1000 and 022.
You can use LEDs as indicator lights, but I do not know enough about the DZ1000 to give you a proper design hint.
The circuit for both will be of this form.
D1 and D2 convert AC (not sure of DZ1000, but positive about 022) to DC for the LED indicators.
D3 and D4 are the LEDs (your color choice, like one green, one red)
R1 and R2 are current limiting resistors to limit current through the LEDs. I believe the DZ1000 will need different resistors than for the 022.
Resistor value calculated using this: Voltage (from switch machine) minus 0.7v (D1 or D2) minus 2.0v (for D3 or D4 green or red LED) divided by 0.020 (20ma max LED current).
The 022 will be sending the same voltage as you supply to the 022 - lets assume 16V ac. So 16v AC will be sent to your new switch circuit. To calculate R1 and R2, 16v - 0.7 - 2.0 equals 13.3v. Now divide 13.3v by 0.020 to get R1 and R2 value of 665 ohms. I believe a common resistor near this value is 680 ohms. You may have to experiment a bit with the R value to get the brightness you want, and that is close to what you get for the DZ1000 using my circuit.
You will have to use a VOM to determine what voltage the DZ1000 sends to it controller. I do not not what this voltage is.
