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I just picked up two PH180s. They both output 18.4v when switched ON, however the ON/OFF switch LED indicator is out on both. Is the LED replacement a "mess" to replace? Maybe it's made into the rocker switch and the entire switch gets replaced? Never had this problem with other PHs.  Thanks to all, in advance

 

 

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They are part of the switch. I replaced the switch on one of them but you could also find the rectangular LEDs and just replace that. The series resistor is a bit small and they lack a diode to protect the LED from back voltage. Here is what I ended up with circuit wise and with the new switch.

PS Switch wiring

PH180switch2

and that's the switch I found on ebay which is the same exact one in the PH.

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  • PS Switch wiring
  • PH180switch2

Agree with Chuck about going nuts when things are broken. So help - i need to replace the switch/LED on my PH180. From above: 1) Am i correct in understanding the LED can be removed without opening up the case? 2) Can you provide the part number of the exact replacement switch/LED assembly? 3) Is the diode and resister something you added on and not part of the original unit? Thank you.

I'll tell you why....like many, my external power supplies, switch controllers, accessory controllers, action controllers, and other items requiring AC power, are kept in a vented cabinet. Occasionally, when a suspect controller or power supply needs attention, I count on indicators to let me know...AT A GLANCE...what's happening with each...it saves me time and aggravation. That's the purpose of them being there in the first place. 

 

This is the exact switch series. 

http://www.lightcountry.com/do...ad/rocker/RA-R19.pdf

Better...

http://www.lightcountry.com/rocker_switch.htm

The dimensions listed are in line with the actual switch I measured with a caliper.

I got mine a few years ago from a kind of surplus guy on ebay. It ended up being the exact one. I do remember taking the original one apart, not sure where it is, but it was repairable by disassembling and replacing the rectangular led as I remember...but not for the faint hearted. They are still making these things...somewhere the switches exist. I guess if I could not get the lighted one, I would also put an LED on the output. When they trip, it is a little unhelpful seeing the lighted LED and no output. I look at the ZW-C optional digital volt/amp meter to see which brick tripped.

Again...jury will be out till I actually give this one a try...look-wise, it's similar, if not the same. From what I can tell, the Light Country switch is discontinued, wherever I've checked.

Product NamePart No.QuantityItem PriceTotal Price
5 Pack Lighted Rocker Switch SPST, 2Vdc to light the switch. Rating 6A/250V. Snap-in. 5/8"x1/2"- With 3" leads
SWT10861$1.95$1.95
<label for="lblSubTotalAmt" id="yiv2048981476lblSubTotal">Subtotal:</label>$1.95
<label for="lblShipFeeAmount" id="yiv2048981476lblShipFee">Shipping & Handling:</label>$6.95
<label for="lblTaxAmount" id="yiv2048981476lblTax">Tax:</label>$0.00

<label for="lblGrandTotalAmount" id="yiv2048981476lblGrandTotal">Order Total:</label>$8.90

Thanks. I think the description is in error on the length. If it's a Light Country R19, then the length is closer to 3/4 inch. The width is right on. The colors of the wires and the solder link to the LED are exactly right. By Jove, I think you've got it! I would bet my $1.95 on it. 

If you cut that soldered link from the black wire to the LED terminal, then 2 vdc does light the LED just as they said on the BG site and you could do that with a simple resistor and diode from the output. The RED wire is the anode of the LED. As it is, with the solder link in place, the circuit above with diode and 10K resistor from the primary side works.

A thought.  The PH180 has been a mild headache since, if there is no power on track, one can't quickly tell if breaker is open or there is a failure in the wiring or TIU or a layout breaker (they were there before PH180).  I connected an external LED which, when out, tells me it's probably the breaker.

PH180switch3Earnie posted:

Or.....try moving the anode lead to the switch LED to the 18v output of transformer.

Move both leads. The minus LED lug is the one soldered to the black wire lug, and the plus LED lug is the one with the red wire. Cut the jumper to the minus LED. Then run the red wire to one side of the output. Then from the minus LED lug, run a resistor, then the anode of a diode and to the other side of the output. Since the output is 18 vac, that comes to about 12 vdc since the LED and diode only conduct half the cycle. 12 vdc minus 2 v for the LED, and .7 v for the diode leaves about 9 vdc to drop with a resistor at say 20 ma. So the resistor should be about 470 ohms. And a 1/4 watt will do it just fine.

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  • PH180switch3
Last edited by cjack

PS%2520Switch%2520wiring

I modified Chuck's diagram to reflect my understanding of the illuminated switch in question.

If this is what it is, I vote against using the switch's internal LED to indicate power at the transformer OUTPUT.  Why?  I can't see the guts of the switch, but I suspect the internal connections from the terminals are bare wires (uninsulated).  This means your 120V house AC wiring and the 18V AC train wiring would be in close quarters.  These are meant to be isolated circuits for all the right reasons (e.g., safety).

Instead, I vote for whoever said to add a 2nd LED which albeit means drilling a 3mm hole in the case...and then adding another few pennies of components (resistor, diode, 3mm round LED) powered by the 18V AC output.

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  • PS%2520Switch%2520wiring
Last edited by stan2004

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