Oops. There is a problem with my recommended inverting circuit.
I thought I was saving you a resistor per inverter-buffer by using a FET. But this only works if directly driven by a digital gate like the CD4017. Instead, in this design there are diodes in the path. So bottom line is you do need a resistor paired with each transistor when you use an N-FET or an NPN. It's just the resistor is hooked up different depending on the method. Sorry for the misdirection.
For driving a few LEDs per transistor as in this case, either method works equally well. If you were going to drive heavier loads I'd suggest the FET method which is more efficient albeit a few cents more per buffer.