We received a new trolley that runs twice as fast on the same voltage as our other 7 trolleys We use 9 volts DC and the new trolley runs a like speed at about 5 volts and there is no opportunity to change the gearing. I thought I had a formula using diodes that would cut the voltage but cannot find it. I want to mount the diodes on the trolley. Anyone have a circuit and formula for me? Thanks .
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Diodes in series (like batteries in a flashlight) will drop about .5 volts for each diode but that voltage drop will be transferred to heat. 4 diodes will get you pretty close to what you want. The diodes have to be capable of handling the maximum current drawn by the trolley.
Ron
Discussed here
www.jcstudiosinc.com/BlogShowT...=413&categoryId=
www.jcstudiosinc.com/BlogShowT...=488&categoryId=
For DC current only 1 set of diodes in one direction is needed as a dropper.
Dale H
Thanks Dale and Ron.Just what I needed, David
Each diode only needs to be able to handle half the total current, since they're conducting only on a half cycle. However, if you're drawing 6 amps, I like to use 6A diodes to give me some headroom.
since they're conducting only on a half cycle.
The OP wrote:
We use 9 volts DC
So there is not much of a cycle.
--Joe
In that case, just use series diodes. 
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