Skip to main content

Q2 is a bi-polar transistor: http://www.mouser.com/Search/R....aspx?Keyword=B772-Y

Q1 is also a bi-polar transistor, I'd probably drop in a 2N2222A if you can't find the exact replacement.  I can't read the number on my PS/1 smoke unit.

R1 & R3 are the smoke resistors, they're 3W wirewound resistors that are in the smoke chamber.

R1 is a 1.8K-ohm 1/4W composition resistor, R2 is a 470 ohm 2 watt wire wound resistor.  I'd use a 1W 13V Zener at D2.

I seriously doubt that Radio Shack has R1, D2, or Q2. 

Why do you "need to rebuild the whole thing"?  Unless the physically destroyed the board it's hard to believe you need to replace some of these parts.

You cannot use a 7805 regulator IC for Q2.  Q1 is transistor. From what I can tell Radio Shack does NOT carry D2 which is a so-called "zener diode" with a value of 13V (probably 1/2 Watt).

 

 

gunrunnerjohn posted:

Q1 is also a bi-polar transistor, I'd probably drop in a 2N2222A if you can't find the exact replacement.  I can't read the number on my PS/1 smoke unit.

Per schematic Q1 is a PNP transistor (2N2222A is NPN).  I can read the Q1 marking on my PS1 board as "A1266" - so search for "A1266 PNP transistor" which appears to have a NTE cross-reference.

 

 

 

trying to figure out what gave up, its easier to rebuild it,,,plan to get the PNPs, and diode,

we have a place called frys electronics, they carry a lot of parts,  they own radio shack,, I think the other places we have are closed today,

the pnp are the ones I think gave up,,the wire wound resistor has some discolor on it,

thanks,,,,

 

BR1; DF04 1A Bridge Rectifier
R1; 1.8K ohm, 1/4 W resistor
R2; 470 ohm 1 W resistor
C1; 330uF, 35V electrolytic cap
IC1; LM78L05 regulator
Q1; 2SA1266 PNP transistor
Q2; 2SB772 PNP transistor
D1; IN4743 13V zener diode

Test for output voltage of rectifier.  Test for 5V at smoke fan motor, check for burned traces.  Check heating elements for open, test for shorted transistors.  G

Last edited by GGG

If the board "cooked" near where the bridge rectifier goes (but the actual bridge rectifier component is located off-board as in your photo) , then there probably is a short in that area.  Even if one or both transistors failed (whether shorted or open) the circuit will generate heat thru one or both smoke resistors.  If you got no heat at all from the smoke resistors and the fan did not spin, this could indeed be explained by a board short near the bridge rectifier.

What kind of multi-meter (if any) do you have?

The printed-wiring on the board is "simple" enough that you ought to be able to see a short by visual inspection.  Can you post a close-up photo of the printed-wiring on your cooked board? 

Photo added; note the red arrow, a solder splash at the tip of the arrow for example would short the output of the bridge rectifier even if your bridge rectifier is off the board.

IMG_0362

Attachments

Images (1)
  • IMG_0362
Last edited by stan2004

That's a PS2/PS3 MTH smoke unit.  It only has the heater resistors and the DC fan motor.  The regulator electronics is on the PS2/PS3 circuit boards which processes the track voltage for both conventional and command operation.   A DIY regulator circuit to drive this for conventional track voltages (as I believe you're using) would be similar in complexity to what you have on the PS1 board.  That is you still need a bridge rectifier, capacitor, a 5V regulator IC (78L05) for the DC fan motor, and some kind of regulator circuitry to drive the heater resistors.

Like your motor, the smoke resistors don't have a voltage max per se.  You just need to limit the power they dissipate.

That PS2 smoke unit has two 16 ohm resistors in parallel making it an 8 ohm load.  Apply your 20V to that and you'll get a whopping 20V x 20V / 8 ohms = 50 Watts which would interesting and probably spectacular...for a few seconds that is.   With an 8 ohm heater load you need to drop the voltage to something like 6V (or so) which would be 6V * 6V / 8 ohms = 4.5 Watts.

The problem with lowering 20V to 6V using a resistor or a typical regulator IC (like a 7806) is that 14V drop goes up as wasted heat.  If you have the space, I'd look at one of those 99 cent eBay regulator modules.  It takes unregulated DC input and generates regulated DC out and is adjustable so you can set it to 6V, 6.5V, 7V, whatever.  You'll already have DC input voltage from your bridge rectifier.

IMG_0363

 

 

Attachments

Images (1)
  • IMG_0363

The reason for the odd arrangement on the PS/1 smoke unit is what Stan is alluding to.  While they are using the same 16 ohm resistors, the PS/2 smoke just wires them in parallel and drives them with a PWM signal from the PS/2 electronics. 

The PS/1 board, OTOH, runs one of the 16 ohm resistors and shorts the other one until the rectified input DC voltage reaches about 13 volts, then turns Q2 off and places the two resistors in series so that you have a resistance of 32 ohms for the higher input voltages.

I've seen the PS/2 smoke unit when the smoke FET shorts on the PS/2 board, things get pretty exciting for a short time before it dies.

with power disconnected measure resistance using meter of each heater resistor.  should measure about 16 ohms each. 

change the voltage from transformer a few volts and make sure the motor stays constant speed.  this will confirm a lot is working right.

as noted earlier, even if one or both of the transistors Q1 and Q2 failed you will generate some heat in the heater resistors.  If you get no warming at all in either of the heater resistors, then a) one of your heater resistors failed "open" (and you won't measure any resistance) or b) there is a break in the printed- wiring  connection from the output of the bridge rectifier to the resistors.

Whoa!  Are you applying power or voltage directly to the heater resistors?  If so, I implore you to cease and desist!

As GRJ suggests above, if you want to see if the circuit is operating as intended you can ramp up the AC voltage input while measuring the DC voltage across each resistor.  At low AC input voltage there will be little if any DC voltage across the resistor attached to the 772 transistor; this is because the 772 is "ON" effectively shorting the resistor.  At high AC input voltage the 772 transistor turns "OFF" allowing DC voltage across the resistor.  When this happens both heater resistors are active with each dropping 1/2 of the available DC voltage from the bridge rectifier.

 

Add Reply

Post

OGR Publishing, Inc., 1310 Eastside Centre Ct, Suite 6, Mountain Home, AR 72653
800-980-OGRR (6477)
www.ogaugerr.com

×
×
×
×
Link copied to your clipboard.
×
×